Question

y = cos (ax²+b) plz derived this equation





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Answer 1

Step-by-step explanation:

$y = \cos(a {x}^{2} + b)$

derivate the equation with respect to x

$\frac{dy}{dx} = \frac{d}{dx} ( \cos(a {x}^{2} + b )$

$\frac{dy}{dx} = - \sin(a {x}^{2} + b) . \frac{d}{dx} (a {x}^{2} + b)$

$\frac{dy}{dx} = - \sin(a {x}^{2} + b ) (2ax)$

Answer 2

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Step-by-step explanation:

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