Question

Y= (cos(log(tanx)) find y'

Answer 1

Answer:

y' = { -sin(log(tanx)) (secx)^2 }/ tanx

Step-by-step explanation:

y = cos(log(tanx))

y' = d/dx {cos(log(tanx))}

y' = -sin(log(tanx)) d/dx {(log(tanx))}

y' = -sin(log(tanx)) ( 1/tanx) d/dx (tanx)

y' = -sin(log(tanx)) ( 1/tanx) (secx)^2

y' = { -sin(log(tanx)) (secx)^2 }/ tanx