y=cos x by son x then find dy by dx
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Answer:1 + cot²x
Explanation:
Y= cosx/sinx
Here y = u/v
dy/dx= {v(du/dx)-u(dv/dx)}/v²
So
dY/dx= {sinx ( d[cosx] / dx ) - cosx ( d[sinx] / dx ) } / sin²x
= { sinx•sinx - cosx•(- cosx) } / sin²x
= {sin²x + cos²x} / sin²x
= 1 + cot²x
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