y= Cosec A + Cot A, Prove that 2dy/da + y²+ 1 =0
It is a derivative based question
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Answer:
if `y = cosec @ + cottheta `, prove that `2(dy)/(d theta) + y^2 + 1 = 0
Step-by-step explanation:
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Answer:
dy/da = (-cotA.cosecA) + (-cosec²A)
Step-by-step explanation:
to prove 2dy/da = y²+1=0
dy/da = -cotA.cosecA - cosecA.cosecA
take - cosec A common
= -cosecA (cotA+cosecA)
= -cosecA(y)
multiply both sides by 2
(shortened)
so we get 2dy/da = 1+y²
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