Y=cosec inverse [1/4cos cube 2x-3cos2x
Answers
Answered by
0
Step-by-step explanation:
We need
tan
2
x
+
1
=
sec
2
x
The function is
y
=
2
3
ln
(
1
+
3
cos
2
x
)
The derivative, by the chain rule is
d
y
d
x
=
2
3
⋅
1
1
+
3
cos
2
x
⋅
3
⋅
2
cos
x
⋅
(
−
sin
x
)
=
−
4
cos
x
sin
x
1
+
3
cos
2
x
Divide by
cos
2
x
d
y
d
x
=
−
4
cos
x
sin
x
cos
2
x
1
+
3
cos
2
x
cos
2
x
=
−
4
tan
x
3
+
sec
2
x
=
−
4
tan
x
3
+
1
+
tan
2
x
=
−
4
tan
x
4
+
tan
2
x
Answered by
14
Answer:
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