y = cosu , u = -x/3
differentiate
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Hi !!
Solution :- y = cosu
Differentiating y = cosu with respect to x
dy/dx = d(cosu)/dx
dy/dx = - sinu ----+-+(1)
And now diffrentiating u = -x/3 w.r to x
dy/dx = d(-x/3)/dy
dy/dx = -1/3 ---------(2)
from (1) and (2)
dy/dx = -sinu (-1/3)
dy/dx = sinu/3 Answer ✔
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Hope it helps you !!!
@Raj❤
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