Question

y + cosx = sinx hoto dy/dx kya hoga​

Answer 1

Answer:

cosx +sinx

Step-by-step explanation:

$- > y = \sin(x) - \cos(x)$

Now differentiating both side with respect to x

$= > \frac{dy}{dx} = \frac{d(sinx)}{dx} - \frac{d(cosx)}{dx}$

Now using formula of differentiation for trigonometric function.

$= > \frac{dy}{dx} = cosx - ( - sinx) \\ = > \frac{dy}{dx} = cosx + sinx$