Question

y=cot^-1(1+x/1-x) find dy/dx

ANSWER:

d/dx (cot^-1) = -1/1+x^2

y=cot^-1(1+x/1-x)

diff w.r.t x

dy/dx=d/dx(cot^-1(1+x/1-x×))

dy/dx=-1/1+(1+x/1-x)^2 × d/dx(1+x/1-x)

dy/dx=-1(1-x)^2/(1-x)^2+(1+x)^2 × (1+x)' (1-v) - (1+x) (1-x)'/ (1-x)^2

dy/dx= -(1-x)^2/(1-x)^2+(1+x)^2×1-x+(1+x)/(1-x)^2

= -2/1+x^2-2x+1+x^2+2x

= -2/2+2x^2

= -1/1+x^2
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Answer 1

Above answer is correct....