y cube + 27 Z cube minus 18 x square + 8 x cube
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Sorry but can you please send me messages about what you have to do with the question like to simply or find x y or z sorry if you don’t tell I can’t solve
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Answer:
(2x + y + 3z)[4x2 + y2 + 9z2 – 2xy – 3yz – 3zx]
Step-by-step explanation:
8x^3 + y^3 + 27^3 - 18xyz
= (2x)^3 + y^3 + (3z)^3 - 3 * 2x * y * 3z
=(2x + y + 3z)[4x2 + y2 + 9z2 – 2xy –
Since, a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 +c^2 - ab -b
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