y+dy/dx(1+x^2)tan^-1x=0
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y + dy/dx( 1 + x²)tan-¹x = 0
y.dx +(1 + x²)tan-¹x .dy=0
=> ydx = tan-¹x.(1+ x²)dy
=> ∫dx/(1 + x²).tan-¹x= -∫dy/y
inegrate both sides,
=> ln(tan-¹x) = -lny + C
ln(tan-¹x)+ lny = C
=>ln{y.tan-¹x} = C
=> y.tan-¹x = K
y.dx +(1 + x²)tan-¹x .dy=0
=> ydx = tan-¹x.(1+ x²)dy
=> ∫dx/(1 + x²).tan-¹x= -∫dy/y
inegrate both sides,
=> ln(tan-¹x) = -lny + C
ln(tan-¹x)+ lny = C
=>ln{y.tan-¹x} = C
=> y.tan-¹x = K
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