Question

y=e^1/2loge(tan^2x) where x is 0 to pie/2 find dy/dx ???

Answer 1

Answer:

sec^2x

Explaination:

y= e^1/2loge(tan^2x)

y= e^loge((tan^2x)^(1/2))

ie,

y=(tan^2x)^1/2 =tan x

therefore,

dy/dx= sec^2x