Question

y= e^2x + e^5x derivative the foll function​

Answer 1

Answer:

2e^2x+5e^5x

Explanation:

dy/dx=e^2x d/dx(2x)+e^5x d/dx(5x)

dy/dx=2e^2x+5e^5x

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Answer 2

$y = {e}^{2x} + {e}^{5x}$

Differentiating both sides w.r.t. x

$\frac{dy}{dx} = \frac{d}{dx} ( {e}^{2x} ) + \frac{d}{dx} ( {e}^{5x} )$

Using the chain rule

$\frac{dy}{dx} = \frac{d}{dx} (2x) \frac{d}{d( {2x}) } ( {e}^{2x} ) + \frac{d}{dx} (5x) \frac{d}{d(5x)} ( {e}^{5x} )$

.

$\frac{dy}{dx} = 2 {e}^{2x} + 5 {e}^{5x} = {e}^{2x} (2 + 5 {e}^{3x})$