Question

y=e^3logx+2x find dy/dx​

Answer 1

Given: The term y = e^(3logx + 2x)

To find: dy/dx​

Solution:

• Now we have given:

                  y = e^(3logx + 2x)

• Differentiating it w.r.t. x, we get:

                  d(e^(3logx + 2x))/dx = e^(3logx + 2x) × (3/x + 2)

                                                     = (2x + 3)/x × e^(2x) × e^(3logx)

​                                                   = ((2x+3)/x) × x^3 × e^2x            

Answer:

                 So dy/dx is ((2x+3)/x) × x^3 × e^2x.