Question

y = e^(3logx) find dy/dx

Answer 1

Answer:

$\frac{dy}{dx}=3x^2$

Step-by-step explanation:

Formula used:

$\frac{d(x^n)}{dx}=nx^{n-1}$

$nlog_a{M}=log_a{M^n}$

$e^{log_eA}=A$

Now,

$y=e^{3logx}$

$y=e^{logx^3}$

$y=x^3$

Differentiate with respect to x

$\frac{dy}{dx}=\frac{d(x^3)}{dx}$

$\frac{dy}{dx}=3x^2$