Question

y= e^ax - e^-ax/e^ax + e^-ax

Answer 1

Answer:

Letf(x)=eaxLetf(x)=eax

f′(x)=aeaxf′(x)=aeax

f′′(x)=a2eaxf″(x)=a2eax

f′′′(x)=a3eaxf‴(x)=a3eax

⋮⋮

fn(x)=aneaxfn(x)=aneax

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