Question

y= e power x log(sin2x)

Answer 1

Answer:

e^x (2 tan 2 x + log (sin 2 x)

Step-by-step explanation:

Given Y= e power x log(sin 2x)  find dy/dx

Now we need to differentiate on both sides we get

Dy/dx = d/dx ( e^x log sin 2 x)

         = e^x d/dx (log sin 2 x) + log sin 2 x d/dx (e^x)

         = e^x 1/sin 2 x d / dx(sin 2 x) + e^x log sin 2 x

       = e^x 1/sin 2 x (2 cos 2 x) + e^x log sin 2 x

       = e^x(2 tan 2 x + log sin 2 x)

So dy/dx = e^x (2 tan 2 x + log (sin 2 x)