Question

y=e^x-e^-x/e^x+e^-x prove x=1/2log(1+y/1-y)

Answer 1

Answer:

Given,

y=xe

x

Now differentiating both sides with respect to x we get,

dx

dy

=xe

x

+e

x

or, x

dx

dy

=x

2

e

x

+xe

x

or, x

dx

dy

=(x+1)e

x

#HAVE A NICE DAY

Answer 2

Answer:

Hope this attachment helps you