y=e^x.sinx,find dy/dx
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Answer:
use UV rule ans:e^xcosx+sinx.e^x
Explanation:
[d/dx(uv)=u.dv/dx+v.du/dx]
dy/dx
=d/dx(e^x.sinx)=e^x.d(sinx)/dx+sinx.d(e^x)/dx=e^x.cosx+sinx.e^x
AS DERIVATIVE OF SINX AND e^x ARE COSX AND e^x respectively with respect to x
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