Question

y gram o3 has same number of oxygen atom as in 100 gram caco3 calculate y

Answer 1

Answer:

100 g of Calcium Carbonate (100,000 mg of Calcium Carbonate) has 3 moles of Oxygen atoms = 3 x 6.022 x 10^23 Oxygen atoms

Answer 2

The value of 'y' is 48 g.

Given,

Mass of CaCO₃ = 100 g

Mass of O₃ = y g

The number of oxygen atoms in 100 g CaCO₃ is the same as in y g O₃

To Find,

The value of 'y'

Solution,

The molar mass of CaCO₃ = 100 g

Given, that the mass of CaCO₃ = 100 g

Moles of CaCO₃ = $\frac{Given mass}{Molar mass}$

Moles of CaCO₃ = $\frac{100}{100}$

Moles of CaCO₃ = 1 mole

By Stoichiometry,

1 Mole of CaCO₃ contains 3 moles of oxygen

Also, 1 mole of any substance contains Nₐ particles, where Nₐ is Avogadro's Number.

Nₐ = 6.022 x 10²³

Thus, 3 moles of oxygen will contain = 3 x Nₐ atoms

3 moles of oxygen will contain = 3 x 6.022 x 10²³ atoms

3 moles of oxygen will contain = 18.066 x 10²³ atoms

Similarly, 1 mole of O₃ contains 3 x Nₐ atoms of oxygen

1 mole of O₃ contains = 3 x 6.022 x 10²³ atoms

1 mole of O₃ contains = 18.066 x 10²³ atoms

Thus 'y' should be equal to the mass of 1 mole of O₃

The molar mass of O₃ = 48 g

Hence, the value of 'y' is 48 g.

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