Question

Y has to score 40% marks to pass. He gets 20 marks and fails by 40 marks. The maximum marks of the exam are?

Answer 1

Let us take the maximum marks be x.

Then 40% of x = 40x/100.

Marks obtained by y = 20.

Marks by which he fails = 40.

Therefore passing marks = 40+20=60.

Atq, 40x/100=60.

or 40x = 60×100

Therefore x = 60×100/40

= 150

Answer 2

Answer:

The maximum marks of the exam are 150.

Step-by-step explanation:

• Let the maximum marks of the exam is x.
• Passing marks of the exam or the marks above which no one can fail is 40 % of the total marks. the passing marks are given by 0.4x
• Marks scored by Y are 20.
• Marks by which Y fails is 40.
• Total passing marks = marks got by Y + Marks by which Y fails.

      $Passing\ marks= 20+40=60$

• Equating both passing marks,the equation formed is

         $0.4x=60$

• On solving, the value of x is 150

Conclusion:

The maximum number of marks of the exam is 150.