Х y If (x2 + y2)(a + b2) = (ax + by)?, prove that = a b?
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(a+b)2=a2+b2+2ab,(a−b)2=a2+b2−2ab
Given (x2+y2)(a2+b2)=(ax+by)2
x2(a2+b2)+y2(a2+b2)=(ax)2+(by)2+2(ax)(by)
⟹a2x2+b2x2+a2y2+b2y2=a2x2+b2y2+2abxy
⟹b2x2+a2y2=2abxy
⟹(bx)2+(ay)
(b×=y)
x = y
a=b
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