y is 1/3 times as large as x
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Let the larger number be x and the smaller number be y.
Then, according to the question.
3x=4y+8
3x−4y=8 .......(1)
And, 5y=3x+5
3x−5y=−5 .....(2)
Solving equation 1 and 2, we get,
x=20 and y=13
Therefore, the required numbers are 20 and 13.
Step-by-step explanation:
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