Y is equal to a cos 3x + b sin 3x then find d squarey upon DX square
Answers
Answered by
3
d²y/dx² = - 9y
Step-by-step explanation :
Given, y = a cos3x + b sin3x ..... (1)
Now differentiating both sides of (1) no. equation with respext to x, we get
dy/dx = - 3a sin3x + 3b cos3x ..... (2)
Again differentiating both sides of (2) no. equation with respect to x, we have
d²y/dx^2 = - 9a cos3x - 9b sin3x
= - 9 (a cos3x + b sin3x)
= - 9y, by (1)
Therefore, d²y/dx² = - 9y
Related question :
if ax^2+2hxy+by^2=1 then (d^2y)/(dx^2)=(h^2-ab)/(hx+by)^3 - https://brainly.in/question/15904397
Answered by
1
Step-by-step explanation:
- We know that
and
- Here it is given that
...1)
- On differentiating above equation with respect to x, we get
So it be can written as
...2)
- Again on differentiating above equation with respect to x, we get
...3)
- From equation 1) and equation 3), we can write above equation
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