Question

Y is equal to root 3 X square + 4 x + 5 differentiation​

Answer 1

Given that,

y=√3x²+4x+5

To find dy/dx

Note:

•Differentiation of any constant value of is zero.

★Using the formula,

$\sf{nx {}^{n - 1}}$

Now,

$\sf{\frac{dy}{dx}} \\ \\ = \sf{\frac{d( \sqrt{3}x {}^{2} + 4x + 5) }{dx}} \\ \\ = \sf{ \frac{d \sqrt{3}x{}^{2} }{dx} + \frac{d(4x)}{dx} + \frac{d(5)}{dx} } \\ \\ = \huge{\sf{2 \sqrt{3}x + 4 }}$