Question

Y is equal to root x minus one by root x whole square find DY by DX ​

Answer 1

Answer:

$y = \frac{\sqrt{x - 1} }{\sqrt{x} } \\\\=> \frac{dy}{dx} = \sqrt{x}*\frac{1}{\sqrt{x - 1} } - \sqrt{x - 1} * \frac{1}{\sqrt{x} } / x^{2} \\We know that the formula \frac{d}{dx} (\frac{U}{V}) = (V dU - U dV) / V^{2}\\ => \frac{dy}{dx} = \frac{(x - x + 1)x^{2} }{\sqrt{x (x - 1)} }\\ => \frac{dy}{dx} = \frac{x^{2} }{\sqrt{x^{2} - x} } \\ => \frac{dy}{dx} = \frac{x\sqrt{x} }{\sqrt{x - 1} }$

Explanation:

Hope it may helps u