Question

y is inversely proportional to x^3. If y = 3 when x = 2, find:

a) the constant of proportionality

b)the value of y when x = 4

c)the value of y when x = 6

d) the value of x when y = 24.​

Answer 1

Answer:

x directly propotionaly

Let "k" be constant..

x = k \times yx=k×y

10 = k \times 510=k×5

10 \div 5 = k10÷5=k

therefore K = 2

ACCORDING TO QUESTION...

x = k \times yx=k×y

x = 2 \times 6x=2×6

x = 12x=12

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