Question

y is older than xby 7 15years ago x age was3/4th of y age what is the present age
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Answer 1

Answer:

Let their present ages be X and Y

Now, Y is 7 years older than X

Y = X+7

15 years ago their ages were

X-15 and Y-15

Y-15 = X+7–15= X-8

15 years back X age was 3/4 of Y's age

X-15 = 3/4(Y-15)

X-15 = 3/4(X-8)

4X-60=3X-24

X= 36

Y= X+7= 43

Thus their present ages are 36yrs and 43yrs

I hope this helps:)