Math, asked by namanbhalla73, 1 year ago

y IV III. TIMU LITE MICI5TL
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Luwulu
19. Running at an average speed of 40 km/h, a bus completes a journey in 9-hours.
How much time will the return journey take if the speed is increased to 45 km/h?
20 Factorise

Answers

Answered by crazy789wadhwani777
0

The first you will need to do is write all the given values

Remember to use the speed formula(D=S×T)

Given:

D=? >we have to use this to find the

T=6 hour>distance,so that we can findhow

S=45km/h>fast must it travel to reach the >given distance in given time.

Formula:D=S×T

Calculation: D=(45km/h)*6h {h and h will get cancel,according to algebra}

D=270Km

Now that we have found out he distance we will again apply the speed formula but this time the SPEED will be left as question mark.

Given:

D=270km

T=5hour

S=?

Formula:S=D/T

Calculation:S=270km/5h

S=54km/h

Speed=54km/h

I hope this will help you. mark as Brainliest.


surinder054: In 8 hours
janhavi2706: so i am right
surinder054: yeah
crazy789wadhwani777: I am right
namanbhalla73: in 9 hourr
crazy789wadhwani777: ....
janhavi2706: no it is 8 because 45×8=360
crazy789wadhwani777: ......
janhavi2706: why are you just typing ......what we will understand
Answered by janhavi2706
0

speed= 40km/h

time= 9 hr

distance = speed × time

= 40×9

= 360 km

if speed is 45km/HR

then also distance will be constant

so, time required will be= distance÷speed

= 360÷45

= 8 hr

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