Math, asked by Anna4433, 3 months ago

y=ln(2x^4+7x+cos(x)) find y`
can anyone solve this?​

Answers

Answered by rakeshoinam8605
0

Answer:

y' = d/dx{ln(2x^4+7x+cos(x))}

=>y' = {1/(2x^4+7x+cos(x))}(8x^3+7-sin(x))

=>y' = (8x^3+7-sin(x))/(2x^4+7x+cos(x)).

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