Question

y=ln√x/x then dy/dx​

Answer 1

Explanation:

$y = ln( \frac{ \sqrt{x} }{x} ) \\ \frac{dy}{dx} = \frac{1}{ \frac{ \sqrt{x} }{x} } \times \frac{d( \frac{ \sqrt{x} }{x}) }{dy} \\ = \frac{x}{ \sqrt{x} } \times \frac{ -1 }{2 \sqrt{x}x } \\ = \frac{ - 1}{2x}$