y =log(ax)^x calculate dy/dx
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4
y = x log(ax)
differentiate with respect to the power x...
dy/dx= x. (1/ax).a + log(ax)
=1+log(ax)
hope it will help you.. thanks
differentiate with respect to the power x...
dy/dx= x. (1/ax).a + log(ax)
=1+log(ax)
hope it will help you.. thanks
Naslinsk:
make it brainlist please
Answered by
1
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Answer is given in the attachment. Hope it helps
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