Question

Y=log base(rootx) x find dy/dx

Answer 1

Answer:

✎y'=1ln(10)⋅1x .

Step-by-step explanation:

From change of base we have

log10(x)=log10(x)=ln(x)ln(10) . 1ln(10) is just a constant multipler. Doing the problem this way gives a result of y'=1ln(10)⋅1x .