Question

Y=log(cotx) differentiate it in the form of dy/dx

Answer 1

Step-by-step explanation:

$y = log( \cot(x) ) \\ let \: u = \cot(x) \\ y = log(u) \\ \frac{dy}{du} = \frac{1}{u} \\ \frac{du}{dx} = - { cosec}^{2} (x) \\ \frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx} \\ = \frac{1}{u} \times - {cosec}^{2} (x) \\ = \frac{ - {cosec}^{2}(x) }{ \cot(x) }$

Hope this helps you