Question

y= log [ ex. sin^5x) Find dy/dx​

Answer 1

Answer:

ANSWER

Given that y=log(sinx), we need to find the value of

dx

dy

We know that the derivative of log(x) w.r.t x is

x

1

⟹

dx

dy

=

dx

d

(log(sinx))=

sinx

1

×

dx

d

(sinx)=

sinx

1

×cosx=cotx

Hence,

dx

dy

=cotx

Step-by-step explanation:

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Answer 2

Answer:

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