Math, asked by ps126570, 6 hours ago

y=log[secx]then dy/dx

Answers

Answered by senboni123456
1

Step-by-step explanation:

We have,

 \rm \: y =  log( \sec(x) )

 \implies \tt \:  \frac{dy}{dx}  =    \frac{1}{ \sec(x) } .  \sec(x). \tan(x)   \\

 \implies \tt \:  \frac{dy}{dx}  =    \tan(x)   \\

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