Question

y=log[secx]then dy/dx

Answer 1

Step-by-step explanation:

We have,

$\rm \: y = log( \sec(x) )$

$\implies \tt \: \frac{dy}{dx} = \frac{1}{ \sec(x) } . \sec(x). \tan(x)$

$\implies \tt \: \frac{dy}{dx} = \tan(x)$