Y=log(sin(cos3x))
Find dy/dx
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ans is attached above ok......
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Step-by-stepxplanation:
dy/dx. 1/y=d/dx(log(sin(cos3x))
=1/sin(cos3x).d/dx(sin(cos3x))
=1/sin(cos3x).cod(cos3x).d/dx(cos3x)
=cos(cos3x)/sin(cos3x).-sin(3x).d/dx(3x)
=3cot(cos3x).(-sin3x)
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