Math, asked by mitali8440, 7 months ago

Y = log(√sinx) find dy/ dx

Answers

Answered by tushar8138

0

Step-by-step explanation:

the differentiation of the given equation is

dy/dx = (1/√sin x ) * 1/2√sinx * cosx

dy/dx = cos x / 2sinx

dy/dx = cot x / 2

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