Question

y=log(x+1)then dy by dx is

Answer 1

Answer:

It's too easy

Step-by-step explanation:

Since y = ln (x+1),

$\frac{dy}{dx} = \frac{d( ln(x + 1)}{dx} \\ = \frac{d( ln(x + 1)) }{d(x + 1)} \times \frac{d(x + 1)}{dx} \\ = \frac{1}{x + 1}$

That's the answer.

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