Question

y=log (x^2+3), Find dy/dx​

Answer 1

Step-by-step explanation:

hope it helps you .....

Answer 2

$\huge \red{ \mathfrak{solution}}$

Given:

$y = log( {x}^{2} + 3 )$

To find:

$\frac{dy}{dx}$

Here we use chain rule ,

$\leadsto \: \frac{d}{dx} log( {x}^{2} + 3) \times \frac{d}{dx} (x^{2} + 3) \\ \\ \leadsto \: \frac{1}{ {x}^{2} + 3 } \times( 2x + 0) \\ \\ \leadsto \: \frac{2x}{ {x}^{2} + 3 }$

Formula used :

◆

$\boxed{ \green{ \bold{ \frac{d}{dx} log(x) = \frac{1}{x} }}}$

◆

$\boxed{ \purple{ \bold{\frac{d}{dx} {x}^{y} = y {x}^{y - 1} }}}$