Math, asked by rajv60185, 11 months ago

y=log(x+root1+x^2.find dybydx

Answers

Answered by tarun8639
1

y=log(X+√(1+x^2)

differnciate with respect to X

Dy/dx={1/X+√(1+x^2)}×(1+2x/2√1+x^2)

uppar lcm le liya then

Dy/dx = X+√(1+x^2)/{X+√(1+x^2)}(√(1+x^2))

Dy/dx = 1/√(1+x^2)

I hope it's an answer

Answered by Anonymous
0

Answer:

Hey mate your answer is here

Attachments:
Similar questions