y=log(x+root1+x^2.find dybydx
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y=log(X+√(1+x^2)
differnciate with respect to X
Dy/dx={1/X+√(1+x^2)}×(1+2x/2√1+x^2)
uppar lcm le liya then
Dy/dx = X+√(1+x^2)/{X+√(1+x^2)}(√(1+x^2))
Dy/dx = 1/√(1+x^2)
I hope it's an answer
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Hey mate your answer is here
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