Question

y log y dx + (x - log y) dy = 0.

Solve the differential equation​

Answer 1

ylogydx−xdy=0

ylogydx=xdy

ylogy

dy

=

x

dx

Let logy=t

y

1

dy=dt

∫

t

dt

=∫

x

dx

logt=logx+logc

logy=cx