Question

y=log₁₀(x²+1),Find dy/dx for the given function y wherever defined

Answer 1

Hope it helps you...

please mark me as brainliest....

Answer 2

given function , $y=log_{10}(x^2+1)$

differentiate with respect to x,

$\frac{dy}{dx}=\frac{d\{log_{10}(x^2+1)\}}{dx}$

$=log_{10}e\frac{d\{log_e(x^2+1)\}}{dx}$

$=log_{10}e\frac{1}{x^2+1}\frac{d\{x^2+1\}}{dx}$

$=log_{10}e\frac{1}{x^2+1}(2x)$

$=\frac{2xlog_{10}e}{x^2+1}$

hence, $\frac{dy}{dx}=\frac{2xlog_{10}e}{x^2+1}$