y = loge 2x
dy/dx= ?
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your answer is here
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Answer:
1/2x
Step-by-step explanation:
By property, we know that,
if y=logeX,
then dy/dx is
dy/dx=1/x
Now,
y= loge2X
Thus,
dy/dx=d(loge2X)/dx
=1/2x
Thank you
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