Question

y = (logx)^x + 4^3x
Find dy/dx

Answer 1

Step-by-step explanation:

While finding F'(x) it must be clearly understood that dom(F') is same as

{ x € dom(F) | where F'(x) exists} In the function y = log (4-3x) the domain is

(—∞, 4/3) and in this interval y' = (1/(4–3x))(—3) = 3/(3x—4)

So the correct answer is y' = 3/(3x—4) where x€(—∞, 4/3)