y=mx+c is a line perpendicular to 3y+x=4 and it passes through (1,1) then C =?
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slope is -1/3 of 3y+x=4
then slope of perpendicular is 3 and equation of Line passing through 1,1 with slope 3 is
(y-1)=3(x-1)
y-1=3x-3
3x-y-2=0
then slope of perpendicular is 3 and equation of Line passing through 1,1 with slope 3 is
(y-1)=3(x-1)
y-1=3x-3
3x-y-2=0
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hope it helps you
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