Question

y = p2 +qr (a) Find y when p = –5, q = 3 and r = –7

Answer 1

Answer:

When p = –5, q = 3 and r = –7 then y = 4

Step-by-step explanation:

Given $y = p^2 +qr$

Put p = –5, q = 3 and r = –7

Find $p^2 +qr$

$p^2 +qr = (-5)^2 + 3 (-7)\\= 25 - 21\\= 4$

If $y = p^2 +qr$ then y = 4.

Answer 2

To find : value of $y$ .

Given : $y = p^{2} + qr$ ,  $p =-5 , q = 3$  and  $r = -7$

Solution :

• By  substituting the given values of variables in expression we find the value of $y$ .  
• After substituting the values by performing simple arithmetic expression we find the value of $y$ .

• $y = p^{2} + qr$  

       $y = (-5 )^{2} + (3 ) ( -7 ) \\y =25 -21\\y = 4$

Hence , value of $y$ is $4$  .