Y
Q-2
Q-3
For the given quadratic equation 5x + 3y - 5 state the root.
(A) (1.0)
(B) (2, 1) (C) (-1,-2) (D) (0,1)
State the common difference d for the given A.P.
3 1 1 3
2'2' 2' 2
Point (4-3) is at a Perpendicular distance of ................. from the X-axis.
.
Section-B
Q-4
Answers
Given : Linear Equation 5x + 3y= 5
To Find : Correct Ordered Pair
A) (1.0) (B) (2, 1) (C) (-1,-2) (D) (0,1)
Solution:
5x + 3y= 5
A) (1.0) => 5(1) + 3(0) = 5 => 5 + 0 = 5 => 5 = 5 Satisfied
(B) (2, 1) => 5(2) + 3(1) = 5 => 10 + 3 = 5 => 13 = 5 not satisfied
(C) (-1,-2) => 5(-1) + 3(-2) = 5 => -5 - 6 = 5 => -11 = 5 not satisfied
(D) (0,1) => 5(0) + 3(1) = 5 => 0 + 3 = 5 => 3 = 5 not satisfied
Hence ( 1, 0) is the ordered pair which satisfy linear equation 5x + 3y= 5
the perpendicular distance of the point (3,-4) from x-axis = 4
as this point will be (3 , 0)
Distance = √(3 - 3)² + (-4-0)² = √0 + 16 = √16 = 4
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