Question

y=(root x+1/rootx)^2​

Answer 1

Step-by-step explanation:

${ (\frac{ \sqrt{x} + 1}{ \sqrt{x} } )}^{2} \\ \frac{x + 1 + 2 \sqrt{x} }{x} \\ 1 + \frac{1}{x} + \frac{2 \sqrt{x} }{x} \\ 1 + \frac{1}{x} + \frac{2}{ \sqrt{x} }$

Answer 2

Question:

y=(root x+1/rootx)^2

Answer:

$= > y = { (\frac{ \sqrt{x + 1} }{ \sqrt{x} }) }^{2}$

$= > y = \frac{x + 1}{1}$

$= > y = x + 1$

$= > x - y = 1$

Hope this answer helps you ^_^ !