Math, asked by ramadevikora, 11 months ago

y=sec(tan inverse x) then dy/dx=

Answers

Answered by saurbhmoynak02
1

Answer:

dy/dx= sec(tan inverse x). tan( tan inverse x). d/dx(tan inverse x)

dy/dx= sec(tan inverse x). tan( tan inverse x).

1/1+x^2

........ using property (tan(tan inverse x.) = 1)

dy/dx = sec(tan inverse x).1/1+x^2

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