Question

y=sec
$sec(x2 + 1) \div x2 - 1)$

​

Answer 1

Answer:

ANSWER

y=sec

−1

(

x

2

−1

x

2

+1

)

Put x=cotθ.

As we know, cos2θ=

1+tan

2

θ

1−tan

2

θ

Then y=sec

−1

(

1−tan

2

θ

1+tan

2

θ

)=sec

−1

(

cos2θ

1

)=sec

−1

(sec2θ)=2θ=2cot

−1

x.

∴

dx

dy

=

1+x

2

−2

Answered By